2016年1月9日 · Say we have a closed loop system, where the flow Q Q is constant through a pipe. Then, at one segment of the pipe, we make the radius smaller. This causes the resistance R R to be greater, so the pressure P P must be higher as well. So, at this stretch of pipe, the fluid is under greater pressure. Meanwhile, we've made the radius smaller, so that cross-sectional area A A is lower. Then, to ...

2022年4月1日 · In the context of your question, "W = q (Va-Vb)" the "work" there refers to an external agent applying forces (to balance the electrostatic force... so that the displacement is done "slowly" in a quasi-equilibrium way... practically speaking, "moved with a …

2020年5月2日 · I am not sure exactly what your problem is. n n is typically an charge carrier density, so the number of free charges dN d N in your volume would be dN = ndV = nAvddt d N = n d V = n A v d d t, corresponding to a charge dQ = neAvddt d Q = n e A v d d t which gives the right answer. ρfree ρ f r e e is simply another way of writing the free ...

2018年9月19日 · I am very well aware of how to get the damping coefficient experimentally by observing a system in action. Given the dimensions and fluid properties of a theoretical viscous fluid dashpot, how doe...

This is problem 2.40 from Introduction to Electrodynamics by D. J. Griffiths: A point charge q q is inside a cavity (not necessarily spherical or anything similarly regular) in an uncharged conductor. Is the force on q q necessarily zero? What my understanding tells me is that if the charge on the inner surface of the conductor is just enough to cancel the field from the point charge from ...

2015年5月15日 · How do I prove the relation between the vectors of magnetic moment $\vec\mu$ and angular momentum $\vec L$, $$\vec\mu=\gamma\vec L$$ ? Many text books and lecture notes about the principles of

2020年11月1日 · If you are asking why Ek E k should not be 12qV 1 2 q V then the answer is that by definition, kinetic energy is 1 2mv2 1 2 m v 2 and is equal to the potential energy qV q V stored across a potential difference V V, which is also equal to the kinetic energy the particle would gain once it crosses this potential difference.

2015年7月12日 · Could someone show me a simple and intuitive derivation of the Centripetal Acceleration Formula a = v2 / r, preferably one that does not involve calculus or advanced trigonometry?

So I'm studying electrostatics and I came across to two different definitions of potential difference/voltage (because we're in stationary regimes) and I'm having trouble understanding how the

2024年7月3日 · it will take work to move the positive charge from point A to point B, as I must counteract the vertical component of the electric force and so on. You are quite correct that the distance to the negative charge changes as you move, but the total work done is still zero. As you move from A to C along the dashed line the PE decreases and you get work out of the system. For example if the dashed ...