What's the difference between arccos (x) and sec (x)
That's the difference between cos−1(x) cos − 1 (x) and cos(x)−1 cos (x) − 1. The former is an inverse for the composition law, the latter for the pointwise product. Notations are confusing with trigonometric functions, though.
What's the difference between arccos (x) and sec (x)?
2019年7月14日 · arccos x arccos x is a value whose cosine is x x, whereas sec x = 1cos x sec x = 1 cos x. The two kinds of "inverse" trigonometric functions can feel a bit esoteric when you're new to them, but let's pretend cos x = 7x + 12 cos x = 7 x + 12.
What does sec x equal in terms of sin, cos, and/or tan?
2015年9月15日 · sec alpha=1/cos alpha This comes straight from the definition. Secans is defined as inverse of cosine.
How do you simplify #sec(x) cos(x) - Socratic
2015年7月22日 · secx = 1 cosx Thus, secxcosx = 1 If cosx = A H, then secx = H A
What is cosx times secx? - Socratic
2016年1月31日 · 1 Your question is: cosx xx secx The trick to this problem is knowing the trigonometric identity: secx=1/cosx Thus, your problem can be written as cosx xx 1/cosx=cosx/cosx=1 The other inverse trigonometric functions are: cscx=1/sinx cotx=1/tanx
Does $\\operatorname{arcsec}(x) = 1 /\\arccos(x)$?
2014年5月15日 · No, they are not equal. Here is why. We can look at an algebraic approach to arcsec and arccos first: Arccos (x) = y Cos (y) = x 1/sec (y) = x Sec (y) = 1/ x y = arcsec (1/ x) Now, we have established that Arccos (x) = y = arcsec (1/ x), Thus, arccos (x) = arcsec (1/ x) And we have got a neat algebraic proof. Conversely, we can do the reverse by substituting cos for sec in the above equations ...
How do you solve sec^2 (x) - sec (x) = 2? | Socratic
2015年12月4日 · x= \pi + 2k\pi x = \pi/3 + 2k\pi x= -pi\/3 + 2k\pi Since sec (x)=1/cos (x), the expression becomes 1/cos^2 (x) - 1/cos (x) = 2 Assuming cos (x)\ne 0, we can multiply everything by cos^2 (x): 1-cos (x) = 2cos^2 (x). Rearrange: 2cos^2 (x)+cos (x)-1=0. Set t=cos (x): 2t^2+t-1=0 Solve as usual with the discriminant formula: t=-1, t=1/2 Convert the solutions: cos (x)=-1 \iff x=\pi+2k\pi cos (x)=1/2 ...
How do you simplify the expression #cosx(secx-cosx)#? - Socratic
2016年10月6日 · How do you simplify the expression cos x(sec x − cos x)?
Is tan^2x -= sec^2x - 1 an identity? | Socratic
2018年1月9日 · True Start with the well known pythagorean identity: sin^2x + cos^2x -= 1 This is readily derived directly from the definition of the basic trigonometric functions sin and cos and Pythagoras's Theorem. Divide both side by cos^2x and we get: sin^2x/cos^2x + cos^2x/cos^2x -= 1/cos^2x :. tan^2x + 1 -= sec^2x :. tan^2x -= sec^2x - 1 Confirming that the result is an identity.
Are $\\cos^2 \\theta$ and $\\cos \\theta^2$ the same?
2016年2月24日 · Are cos2 θ cos 2 θ and cosθ2 cos θ 2 the same? I mean be it sin, cos, tan, cot, sec, csc sin, cos, tan, cot, sec, csc. Are they same? Please help a maths noob here.