2016年6月9日 · The relation you are alluding to with the asymmetric sign function is $\operatorname{sgn}^+x=2H(x)-1$. $\endgroup$ – Mario Carneiro Commented Jun 9, 2016 at 5:10

知乎，中文互联网高质量的问答社区和创作者聚集的原创内容平台，于 2011 年 1 月正式上线，以「让人们更好的分享知识、经验和见解，找到自己的解答」为品牌使命。知乎凭借认真、专业、友善的社区氛围、独特的产品机制以及结构化和易获得的优质内容，聚集了中文互联网科技、商业、 …

2.x = abs(x)×sgn(x)或者abs(x) = (x)×sgn(x) 3.定义域为（ - ∞， + ∞），值域为 { - 1，0, 1}. 4.sgn是英文sign(标记)的缩写。 [2] 返回函数. 表返回表示数字符号的整数。 Sgn(number) number参数可以是任意有效的数值表达式。 Sgn函数有如下返回值： 如果number为Sgn返回. 大于 …

Let $X$ be a real valued random variable. Let $\operatorname{sgn}(x)$ be $1$ when $x>0$, $-1$ when $x<0$ and $0$ when $x=0$.

2019年10月20日 · Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.

Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.

2022年12月9日 · Here's one way to compute it. We have for $\phi \in C^{\infty}_0$ $$\left<\frac{\partial}{\partial y}\text{sgn}(x-y),\phi\right> = -\left<\text{sgn}(x-y),\frac ...

Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.

2017年9月17日 · Considering derivative of discontinuity as del(x). Derivative of sgn(x) would be 2*del(x), as there exist a discontinuity at x=0 and a change in step by 2 units (from -1 to +1). Note : This method is being used in mathematical modeling of signals. Where del(t) is an unit impluse function. And sgn is made up of two step functions.

Stack Exchange Network. Stack Exchange network consists of 183 Q&A communities including Stack Overflow, the largest, most trusted online community for developers to learn, share their knowledge, and build their careers.