
SOLUTION: the equivalent expression of sin300° is - sin____°
sin(300) = -.8660254038 sin(240) = -.8660254038 they're the same. in the first and second quadrant, the sine function will be the same value but will be positive. sin(60) = .8660254038 sin(120) = .8660254038 the value of the sine function is the same in all 4 quadrant, except that: in the first and second quadrants, it is positive.
SOLUTION: what are the exact values of the six trigonmetric …
300 degrees is in the fourth quadrant. the equivalent angle in the first quadrant would be 360 - 300 = 60 degrees. this is a common angle that you can find the exact trigonometric functions for.
SOLUTION: Evaluate the function without using a calculator. Sin 300
There are 360 degrees in a circe, right? So going around a circle 300 degrees one way, is the same as going 60 degrees the other way. So sin(300)=sin(-60). Now you should know that sin(-x)=-sin(x). So we are down to sin(300)=-sin(60). You should also know that sin(60)= so the answer is: Hope that helps, Kev
SOLUTION: Find the exact value of the trigonometric function. (If …
360 - 300 = 60 5. Find the sin, cos, ... for the reference angle. Since 60 is a special angle, we should know that the sin(60) = 6. Determine the sign of the result. Since the angle terminates in the 4th quadrant and since sin is negative in the 4th quadrant:
SOLUTION: exact value of cos 300 degrees and sin 300 degrees
You can put this solution on YOUR website! exact value of cos 300 degrees Reference angle:: 60 degrees cos(300) = cos(60) = 1/2
SOLUTION: Use reference angles to find the exact value of the …
The sin(300) is in quadrant IV and has reference angle of 60. So, we need sin(60) = sqrt(3)/2
SOLUTION: Use references angles to find the exact value of each ...
Use references angles to find the exact value of each expression. Sin 300 sin 300= sin (180+120) = sin(180)cos(120) + sin(120)cos(180) = 0*cos(120) + sin(120)(-1) = -1sin(120) = -1sin(180-120) since the sinus of two supplementary angles are the same. so sin 300= -1sin60 = -(sqrt 3)/2
SOLUTION: find the exact value, leaving the answer in a proper …
You can put this solution on YOUR website! Sin(-300)-(Sin((360-60))) Sin(A-B) = Sin A Cos B - Cos A SIn B ...
SOLUTION: Please help me solve Find the exact value of a. sin 300° …
300 degrees is in quadrant IV. The reference angle formula for quadrant IV is R = 360 - x where R is the reference angle and x is the given angle, so, R = 360 - x R = 360 - 300 R = 60 Now use either a 30-60-90 triangle, or a unit circle to find that Because this angle (300 degrees) is in Q4, we know sine is negative Final Answer:
(sin^2)(225degrees)-(cos^2)(300degrees) - Algebra Homework Help
(sin^2)(225degrees)-(cos^2)(300degrees)-----The reference angle for 225 degrees is 45 degrees in the 3rd quadrant sin(225) = -sin(45) = (sqrt(2))/2 So, sin^2(225) = 2/4 = 1/2-----The reference angle for 300 degrees is 60 degrees in the 4th quadrant. cos(300) = cos(60) = 1/2 So, cos^2(300) = (1/2)^2 = 1/4-----Ans: 1/2 - 1/4 = 1/4