How do I find the value of $$ sin \ \ ( 330)$$? - Toppr
We know from trigonometry that, $$ sin(A-B)=sin \quad A.cos \quad B-cos \quad A. sin \quad B $$ $$\therefore sin\ 330=sin (360-30)$$
SOLUTION: Sin420°cos390 - cos(-300°)sin(-330°) - Algebra …
You can put this solution on YOUR website! sin(420°)*cos(390°) - cos(-300°)*sin(-330°) = sin(420°) = sin(60°); cos(390°) = cos(30°); cos(-300°) = cos(60 ...
What is the value of sin 420^o . cos 390^o + cos (-300^o ) . sin
Click here👆to get an answer to your question ️ what is the value of sin 420o cos 390o cos 300o
Prove that:cos 570^o sin 510^o+sin (-330^o)cos (-390^o)=0
Without using calculator, find the value of cos 570 o. sin 510 o + sin (− 330 o). cos ...
Prove thatcos 570^{circ} sin 510^{circ} - sin 330^{circ} cos ... - Toppr
Click here:point_up_2:to get an answer to your question :writing_hand:prove thatcos 570circ sin 510circ sin 330circ cos 390circ 0
How do I find the value of $$ cos 330 - Toppr
$$ 330^0 = 360^0 - 30^0 $$ so $$ cos (330^0) = cos ( 360^0 -30^0 ) = cos ( 360^0) cos (30^0) + sin (360^0 ) sin ( 30^0) $$ The cosine, sine, tangent and secant of $$ 360^0 $$ equal the cosine, sine, tangent and secant of $$0^0 $$ respectively.
sin 120^∘cos 150^∘ - cos 240^∘sin 330^∘ is equal to - Toppr
>>Trigonometric Functions >> Trigonometric Functions Trigonometric Functions >> sin 120^∘cos 150^∘ - cos 240^∘sin 330^∘ sin 120^∘cos 150^∘ - cos 240^∘sin 330^∘
Prove that cos 570^∘sin 510^∘ - sin 330^∘cos 390^∘ = 0 - Toppr
Click here👆to get an answer to your question ️ Prove that cos 570^∘sin 510^∘ - sin 330^∘cos 390^∘ = 0 . Solve Study Textbooks Guides Join / Login
Prove thatsin 40^{circ} cos 390^{circ} + cos (-300^{circ})sin (-330 ...
Click here:point_up_2:to get an answer to your question :writing_hand:find the value of displaystyle sin 420circcos 390circcos left 300circ right sin left
Show that sin ( - 420^∘ )cos (390^∘) + cos ( - 660^∘ )sin (330^∘)
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