
How do you find the limit of # sin(7x)/x# as x approaches 0?
2016年7月14日 · There are "two" ways to solve this limit. The first way to do is it algebraically, and the second way is to apply L'Hospital's rule (although this is technically incorrect - even though …
How do you simplify sin 2x times sin7x? - Socratic
2016年12月1日 · Use the exponential form of the trigonometric functions: #sin(7x) = (e^(7ix) - e^(-7ix))/(2i)# #sin(2x) = (e^(2ix) - e^(-2ix))/(2i)#
How do you simplify sin5x + sin7x? | Socratic
2016年8月31日 · By the Formula, sin C+ sin D= 2sin ((C+D)/2)cos((C-D)/2), sin 5x+sin 7x=2sin6xcos(-x)=2sin6xcosx.
Evaluate the limit. Be sure to show your reasoning. limit as x ...
2018年3月6日 · I know that the bottom turns to sin3x/cos3x and then i multiply the recipricol in which I get the limit as x approaches 0 (sin x7)(cos3x / sin 3x) but I don't know where to go …
How do you find the derivative of #sin^7(x)#? - Socratic
2015年9月17日 · 7cosxsin^6x sin^7x may be wriiten as (sinx)^7 Hence the derivative may be found by using the power rule of differential calculus which says that the derivative of a …
Solve sin7x+cos2x=-2? - Socratic
2018年3月21日 · What are the units used for the ideal gas law?
If x belongs to (0,π/2), the number of solutions of the equation …
2018年6月22日 · Here, #sin7x+sin4x+sinx=0 , where , x in(0,pi/2)# #=>sin7x+sinx+sin4x=0# #=>2sin((7x+x)/2)cos((7x-x)/2)+sin4x=0#
Prove? cotx = sin5x+sin7x / cos5x-cos7x - Socratic
2018年3月21日 · WE have, #color(red)((1)sinC+sinD=2sin((C+D)/2)cos((C-D)/2)# #color(red)((2)cosC-cosD=-2sin((C+D)/2)sin((C-D)/2)#
What is #lim_(x->0) sin(sin3x)/(sin 7x)# - Socratic
2017年9月22日 · 3/7 My first impression is that: lim_(x->0) sin(sin3x)/(sin 7x) = 3/7 since sin theta behaves like theta for small values of theta.
How do you prove that \frac { \cos 7x + \cos 5x } { \sin 7x - \sin 5x ...
2017年11月27日 · How do you prove that #\frac { \cos 7x + \cos 5x } { \sin 7x - \sin 5x } = \cot x#?