Let's assume that for all values of a and b. So now let's just pick arbitrary values for a and b. So let's make and . Start with the given equation. Plug in and Add 2 and 3 to get 5 Take the square root of 2 to get 1.41421. Take the square root of 3 to get 1.73205. Take the square root of 5 to get 2.23607. Add 1.41421 and 1.73205 to get 3.14626

with sqrt(a) * sqrt(b) = sqrt(a*b), you won't find one no matter how many times you try. with sqrt(a) + sqrt(b) = sqrt(a+b), you wan find one very easily as above. the formal proof is probably a lot more complicated so i'll leave that one alone. the best you can do with sqrt(a) + sqrt(b) is factor out the common terms. for example:

To solve this problem, you are going to need to use the base b logarithm formula to rewrite the problem: log[base b]a = c means the same as b^c = a So use this in your problem: log[b] sqrt(b^3) = x a = sqrt(b^3), b = b, c = x Now rewrite as the exponent: b^c = a b^x = sqrt(b^3)

However, the problem says " . . . for any real positive "a", "b" and "c" . . .". Thus, just from wording, I conclude that the hint is irrelevant to the problem. Consider it as my moderate contribution to this problem.

Question 1183334: If sin 15° = 1/2 sqrt[A-sqrt(B)], then, by using a half-angle formula, find A= B= I found that A is 2.

So I will continue to find the values of a and b: Solve the system of equations: Solve the first equation for b: Substitute in the second equation in the system a-6 = 0; a-93 = 0 a = 6; a = 93 For a = 6 For a = 93 Since a b, we choose a = 6 and b = 93 So the radical expression can be expressed as , where Now do yours the exact same way, step-by ...

This Lesson (Prove that if a, b, and c are the sides of a triangle, then so are sqrt(a), sqrt(b) and sqrt(c)) was created by by ikleyn(52293) : View Source, Show About ikleyn : Prove that if a, b, and c are the sides of a triangle, then so are , , and

Algebra -> Quadratic Equations and Parabolas -> SOLUTION: using the quadratic formula x=[-b(+-)sqrt(b^2-4ac)]/2a solve quadratic equation x^2 -5 = 0 Log On Quadratics: solvers Quadratics Practice!

Question 1183333: If cos22.5° = 1/2 sqrt[A+sqrt(B)], then, by using a half-angle formula, find: A = 2 B = I found that A equals two, but cant find out what B is.

Prove that if a, b, and c are the sides of a triangle, then so are sqrt(a), sqrt(b), and sqrt(c). ~~~~~ Proof Let assume that + = . (1) where "a", "b" and "c" are the sides of a triangle. I want to lead it to CONTRADICTION. Indeed, square both sides of (1). You will get a + + b = c, or a + b = c - .