Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because tangent is negative in the second quadrant. The exact value of tan(0) tan (0) is 0 0. Multiply −1 - 1 by 0 0.

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because tangent is negative in the fourth quadrant. The exact value of tan(π 3) tan (π 3) is √3 3. The result can be shown in multiple forms. −1.73205080… - …

Apply the reference angle by finding the angle with equivalent trig values in the first quadrant. Make the expression negative because tangent is negative in the second quadrant. The exact value of tan(π 6) tan (π 6) is √3 3 3 3. The result can be shown in multiple forms. −0.57735026… - 0.57735026 …

The value of tan ( (5pi)/9) is -5.67128…

2014年9月28日 · Thus cos2π 5 = √5 − 1 4 and it's easy to compute sin(π / 5) and cos(π / 5) from this. One can use the outlined strategy, too. The key is using π / 10 and not x = π / 5.

Use the basic trigonometric identity: tan (x) = cos (x) sin (x) = cos (6 5 π ) sin (6 5 π ) =

Rewrite 5π as π ⋅ 5+0 = tan(π5+0) Apply the periodicity of tan: tan(x+π ⋅ k) =tan(x) tan(π ⋅ 5+0)= tan(0) = tan(0) = tan(0) = 0. What is the value of tan (5pi) ?

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2017年3月18日 · First, find tan(π 12). Call tan(π 12) = tant ---> Use trig identity: tan2t = 2tant 1 −tan2t. tan2t +2√3tant −1 = 0. Solve this quadratic equation for tan t. tant = − √3 ± 2. Since tan(π 12) is positive, take the positive value. tant = tan(π 12) = 2 −√3.

2015年4月28日 · tan(5pi) -= tan(pi) = 0 and there is no point in using the half angle formula to evaluate (tan(5pi))/12 Therefore, let's assume that you really want to evaluate tan((5pi)/12) Half angle formula (for tan): tan^2(theta/2) = (1-cos(theta))/(1+cos(theta)) tan^2((5pi)/12) = tan(((5pi)/6)/2) =(1-cos(pi/6))/(1+cos(pi/6)) = (1+sqrt(3)/2)/(1-sqrt(3)/2 ...