
How do you simplify #tan(x) cos(x)#? - Socratic
2015年9月22日 · Use the fact that tan (x) = sin (x)/cos (x) tanxcons = sinx/cosx *cosx/1 = sinx
Fundamental Identities - Trigonometry | Socratic
The best videos and questions to learn about Fundamental Identities. Get smarter on Socratic.
Why does tan equal to sin/cos? - Socratic
2015年4月15日 · The best answer to this question depends on the definitions you're using for the trigonometric functions: Unit circle: t correspond to point (x,y) on the circle x^2+y^2 =1 Define: sint = y, , cos t = x, , tant = y/x The result is immediate.
Proving Identities - Trigonometry | Socratic
The functions sine, cosine and tangent of an angle are sometimes referred to as the primary or basic trigonometric functions. The remaining trigonometric functions secant (sec), cosecant (csc), and cotangent (cot) are defined as the reciprocal functions of cosine, sine, and tangent, respectively. Trigonometric identities are equations involving the …
Express tan θ in terms of cos θ? - Socratic
2018年3月11日 · using the trigonometric identities ∙ xtanθ = sinθ cosθ ∙ xsin2θ +cos2θ = 1 ⇒ sinθ = ± √1 − cos2θ tanθ = sinθ cosθ = ± √1 −cos2θ cosθ
How do you simplify #tan(cos^(-1)x)#? - Socratic
2016年4月27日 · . Let a=cos^ (-1)x. Then x= cos a and tan a=sina/cos a=+- (sqrt (1-x^2)/x) Answer:+- (sqrt (1-x^2)/x) .
How do you simplify #cos(arctan(x)) - Socratic
2016年7月26日 · Let a = arctan ( x ). The principal value of a ∈ (− π 2, π 2). Then tana = x and 0 ≤ cosa ∈ [0,1) ( wrongly marked as [ 0, - 1 ], in my previous answer, two years ago). Now, the given expression is cosa = 1 √1 + x2,x ∈ (− π 2, π 2). It is important that cosa ≥ 0, for a ∈ Q1 or Q4. If the piecewise-wholesome general inverse operator (tan)−1 is used, cos(tan)−1x, = ± 1 ...
How do you simplify #tan(x) cos(x)#? - Socratic
2018年3月11日 · color (brown) (sin x tan x * cos x (sin x / cancelcos x) *cancel cos x => sin x
How do you prove #(tan x)(cos x)=sin x#? - Socratic
2018年3月4日 · L.H.S. = (tanx)(cosx) = (sinx cosx)(cosx) = sinx = R.H.S [As we know that tanθ = perpendicular base = perpendicular hypotenuse base hypotenuse = sinθ cosθ] Hope it helps.
How do you simplify #tan x cos x csc x#? - Socratic
2015年7月22日 · The values of x where this is not true are those values of x which make either cos (x)=0 or sin (x)=0. One of these will happen at each value of x that is an integer multiple of pi/2 radians (90 degrees).