Feb 19, 2020 · Your working isn't that clear. The potential is the negative of the work done by the field to bring $1C$ from a point of zero reference (usually set at infinity) to the specified position.

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May 8, 2024 · V=Kq/r for a positive point charge. Assume B is the closest distance of approach for any test charge without experiencing a force due to the positive point charge. Now, if I want to move the point charge further towards point A, wouldn't I be performing negative work, and hence the point would have negative potential?

May 3, 2021 · A cube of side 20 cm has its center at the origin and its one side is along the x-axis, so that one end is at x = +10cm and the other is at x = -10cm. The magnitude of electric field is 100 N/C and...

May 8, 2019 · So I have a few questions regarding a Van De Graff Generator. With the Equation: V=kQ/r where V is the Voltage Potential, k is the constant, Q is the charge in coulombs and r is the radius of the sphere. 1.) Do I have to use a sphere? Can I use, say a cylinder that is metal? 2.) How does the Charge concept work?

Jul 28, 2020 · The formula V = kQ/R gives the potential at the surface of a spherically symmetrical charge, Q, of radius, R (on the surface of your shell). It is found by integrating the, E, field in from infinity. As you point out, the, E, inside the shell is zero, so the potential does not change as you go in from the surface.

Apr 14, 2019 · When dimensions become very small, we are no longer in the realm of classical physics where potentials have mathematical singularities as in the classical 1/r Coulomb potential.

May 23, 2017 · The definition of electric potential is the work done per unit charge in moving the charge from infinity to that distance.

Dec 14, 2014 · Thanks laying out your work so neatly in the question. I think the solution is the following $$\Delta KE= \int_{r_a}^{r_b}{ KQq \over r^2} dr$$

Jan 6, 2022 · The formula for potential V=kq/r doesn't count resistance to be a factor affecting it $\endgroup$