
Solve Using the Quadratic Formula x^2-4x-1=0 - Mathway
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Solve x^2-4x+1=0 | Microsoft Math Solver
4x2-4x+1=0 One solution was found : x = 1/2 = 0.500 Step by step solution : Step 1 :Equation at the end of step 1 : (22x2 - 4x) + 1 = 0 Step 2 :Trying to factor by splitting ...
x^2-4x-1=0 - Symbolab
x^2: x^{\msquare} \log_{\msquare} \sqrt{\square} \nthroot[\msquare]{\square} \le \ge \frac{\msquare}{\msquare} \cdot \div: x^{\circ} \pi \left(\square\right)^{'} \frac{d}{dx} \frac{\partial}{\partial x} \int \int_{\msquare}^{\msquare} \lim \sum \infty \theta (f\:\circ\:g) f(x)
解方程x²-4x+1=0如何解?? - 百度知道
2014年1月9日 · x²-4x+1=0的配方法解答过程如下:(1)把1化成4-3:x²-4x+4-3=0(2)x²-4x+4可以组成一个完全平方式: (x-2)²=3(3)两边同时开根号.
[FREE] Solve x^2 - 4x + 1 = 0. - brainly.com
2023年11月10日 · To solve the equation x^2 - 4x + 1 = 0, we can use the quadratic formula. For an equation of the form ax^2 + bx + c = 0, the quadratic formula is given by x = (-b ± √(b^2 - 4ac)) / (2a). In this case, a = 1, b = -4, and c = 1. Substituting these values into the quadratic formula, we get: x = (-(-4) ± √((-4)^2 - 4(1)(1))) / (2(1))
求解 x^2+4x+1=0 | Microsoft Math Solver
x^{2}+4x+1=0 这样的二次方程式可通过转换为完全平方形式来求解。 要化为完全平方形式,等式必须先转换为 x^{2}+bx=c 的形式。
已知X^2-4X+1=0 求X^2+1/X^2=? - 百度知道
2011年1月11日 · 解:因为x^2-4x+1=0 , 所以 x-4+1/x=0 ,即 x+1/x=4 所以(x+1/x)^2=16,即 x^2+2+1/x^2=16 所以x^2+1/x^2=14
若x^2-4x+1=0,求x^2+1/(x^2)的值,需要过程 - 百度知道
先由x^2-4x+1=0移项得x^2+1=4x,再将x^2+1=4x除以x得x+1/x=4.两边平方得(x+1/x)^2=16 拆开得x^2+1/(x^2)+2=16 移项得x^2+1/(x^2)=14
Solve by Factoring x^2+4x+1=0 - Mathway
Use the quadratic formula to find the solutions. −b±√b2 −4(ac) 2a - b ± b 2 - 4 (a c) 2 a. Substitute the values a = 1 a = 1, b = 4 b = 4, and c = 1 c = 1 into the quadratic formula and solve for x x. −4±√42 −4 ⋅(1⋅1) 2⋅1 - 4 ± 4 2 - 4 ⋅ (1 ⋅ 1) 2 ⋅ 1. Simplify. Tap for more steps... Simplify the expression to solve for the + + portion of the ± ±.
已知x^2-4x+1=0,求x^2+/1x^2_作业帮 - qb.zuoyebang.com
这个可以这样算,比较简便 x^2-4x+1=0所以x不等于0,两边都除以x得到x+1/x=4两边同时平方得x^2+1/x^2+2=16 所以x^2+1/x^2=16-2=14
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