2016年7月14日 · The factors are (x+3) and (x+1) We are asked for factorise: x^2+4x+3 First notice that the function is a quadratic and so will have two factors. Since the coefficient of x^2 …

2016年6月4日 · x=1, 3 you start by finding a number that multiplies to 3 and adds to -4. they will both be negative as the product is positive and the sum negative. your numbers are -1 and -3. …

2017年10月15日 · x^2+4x+3 is already in standard polynomial form. Standard form x^2+4x+3 is already in standard form for a quadratic polynomial. Standard form of a polynomial is a sum of …

2017年7月22日 · How do you solve #x^2+4x+3=0# using the quadratic formula? Algebra Quadratic Equations and Functions Quadratic Formula. 1 Answer

2017年12月16日 · See below Roots (intercepts) Let's first solve this parabola to obtain the roots. Factorise x^2-4x+3: (x-3)(x-1) x-3=0, x-1=0 x=3, x=1 Therefore, the roots are x=3 and x=1 …

2017年10月17日 · The general vertex form is #color(white)("XXX")y=(x-color(red)a)^2+color(blue)b# with vertex at #(color(red)a,color(blue)b#)

2017年2月28日 · How do you solve quadratic inequality, graph, and write in interval notation #x^2 - 8x + 15 >0

2015年7月29日 · color(red)( f(x) = (x-2)^2-1) > The vertex form of a quadratic is given by y = a(x – h)^2 + k, where (h, k) is the vertex. The "a" in the vertex form is the same "a" as in y = ax^2 + …

2015年4月8日 · Answer: => y <= 1 Solution: The range of this function is the set of the values of y that the f can take, So, letting y= f(x) y = -x^2 + 4x - 3 => x^2 - 4x + 3 +y = 0 For real x , b^2 - …

2015年8月11日 · The curve is concave upwards. It is a quadratic function. It has one turning point. Your graph must include that. x^2 has a positive sign. The curve is concave upwards. It has a …