Assertion: Ammonia shows a trigonal pyramidal molecular structure. Reason: In the structure of ammonia, three atoms are attached to the central atom and thus, shows tetrahedral electron pair geometry.

Adding sigma bond and lone pair we get 5+1=6. So, X e will need its s-orbital, three p-orbitals and two of its d-orbitals. So, the hybridization will be s p 3 d 2.

According to the VSEPR theory, the geometry and shape of the molecule depends upon:

The shape of X e F 4 is square planar. The central X e atom has 4 bond pairs of electrons and two lone pairs of electrons.

A compound XeOF4 is present. To Find: The Shape of XeOF4 and bond angle between them. Solution: As we know, Electron pair = valence electron+bond pair Formula for calculating electron pair. Here, V= number of valence electrons. M= no of monovalent atoms attached. C= charge on the cation. A= charge on the anion. So, the XeOF4 electron pair. Bond ...

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The structure of X e F 4 is shown below. The central Xe atom has 2 lone pairs and 4 bond pairs of electrons. The electron pair geometry is octahedral and molecular geometry is square planar.

XeF4 XeF5^- F2SeO2 XeF3^+ XeOF4 ClOF3 ICl4^- SCl2 OSF4. Solve Study Textbooks Guides. Join / Login >> Class 12

Choose the answer below that accurately describes the correct molecular shape for the molecule X e O F 4.

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