Question 1114762: Make up an equation of the form y = kx +b, the graph of which passes through the following points M (5, 5) and N (–10, –19) Answer by rothauserc(4718) ( Show Source ): You can put this solution on YOUR website!

Question 1028064: Make up an equation of the form y = kx +b, the graph of which passes through the following points: A (8, –1) and B (–4, 17) Found 2 solutions by josgarithmetic, Fombitz :

Question 1028068: The line y = kx +b passes through points A (–1, 3) and B (2, –1). Write the equation of the line. Write the equation of the line. Answer by fractalier(6550) ( Show Source ):

Sai 9. asked • 10/17/17 Find the values of k and b if it is known that the graph of y=kx+b goes through points (2, 10) and (−7, −10)

Algebra -> Proportions-> SOLUTION: Suppose y is directly proportional to x (a) If y=8 when x= 13, find k so that y=kx. (b) Then use y=kx to find y when x=3 Log On Algebra: Proportions Section

Question 1203209: If the line l^1 : y=kx+b passes the point (2,3) and is perpendicular to the line y = ½x - 5, what is the equation of the line l^1? Answer by math_tutor2020(3737) ( Show Source ):

2016年4月7日 · The line y=kx-5 is given in slope-intercept form [y=mx+b, where m is slope and (0,b) is the y-intercept]. The value k is the slope of the line. The -5 is the y-intercept, the point (0,-5).

The intercept form of a line is: where a is the x-coordinate of the x-intercept and b is the y-coordinate of the y-intercept. This is somewhat analogous to the equation for an ellipse whose center is at the origin and whose x-intercepts are (帶,0) and whose y-intercepts are (0,帳).

2019年7月18日 · Doug C. Hi Mark H. By experimenting on Desmos with the graph of the circle and the graph of various lines where y = kx, along with the fact that the right triangle created by joining (3,1) with the points of intersection will have a hypotenuse = sqrt(10), I think k has a value very close to 1.1282.

2012年10月22日 · For the line y=kx+b, k is the slope. For two lines y=k 1 x+b 1 and y=k 2 X+b 2 , When K 1 =K 2, two lines are parallel; when K 1 =-1/k 2, two lines are perpendicular. It doesn't matter whatever b 1, b 2 are. Hence to save time, you only need to calculate k 1 and k 2. To calculate the slope k of any line, you have to change the equation to y=kx+b