2014年8月18日 · The derivative of tanx is sec^2x. To see why, you'll need to know a few results. First, you need to know that the derivative of sinx is cosx. Here's a proof of that result from first …

2018年7月6日 · By definition: #d/dx tanx = lim_(h->0) (tan(x+h)-tanx)/h# Using the trigonometric formulas for the sum of two angles:

2015年10月10日 · Domain: (theta|theta!=kpi/2, where k is an odd integer) Range: (-oo,oo) Remember that tan=sin/cos therefore, you will have a vertical asymptope whenever cos=0. …

From the derivative of \\sin(x), \\cos(x) and \\tan(x) can be determined. \\cos(x) can be found by using the chain rule and the identity \\cos(x)=\\sin(x+90). \\tan(x ...

2015年9月21日 · graph{tan x [-10, 10, -5, 5]}. See explanation. graph{tan x [-10, 10, -5, 5]} The number of lines you have to draw depends on the domain provided. If the domain is not …

If tanx =3/4, π < x <3 π /2, find the values of sin (x/2), cos (x/2) and tan (x/2)? Question #07cd9.

2016年11月4日 · dy/dx = sec^2x By definition If y=f(x) then: dy/dx=f'(x) =lim_(hrarr0)( (f(x+h)-f(x))/h ) So, with y=tanx we have: dy/dx = lim_(h rarr0)((tan(x+h)-tanx)/h) Using the ...

2016年12月9日 · Use logarithmic differentiation. Use the natural logarithm on both sides: ln(y) = ln(ln(x)^tan(x)) Use the property of logarithms ln(a^b) = (b)ln(a) ln(y) = tan(x)ln ...

2015年1月29日 · The period of y=tanx is pi. In fact: graph{tanx [-10, 10, -5, 5]}. The "fundamental" branch is in (-pi/2,pi/2

2017年7月28日 · y = -2cos^2(x)+3cos(x) The given equation, y'+ytan(x)=sin(2x) , is of the form: y' + P(x)y = Q(x) Where P(x) = tan(x), and Q(x) = sin(2x) It is known that the integrating factor is: …