
为什么硫化锌与氧气反应生成氧化锌而不是锌单质和二氧化硫?
Zn是活泼金属,容易与氧气发生反应。 这样也可以看到,锌会被继续氧化。 生成的是 氧化锌 和二氧化硫。 锌单质是不会形成的,包括在水溶液中,因为锌是氢前金属,而氧气又是一种常用的中强性 氧化剂。 但硫的话在水溶液中,可能会生成 单质硫,如加压浸出硫化锌精矿时,也能生成二氧化硫,如硫化锌精矿氧化焙烧时。 知乎,中文互联网高质量的问答社区和创作者聚集的原创内容平台,于 2011 年 1 月正式上线,以「让人们更好的分享知识、经验和见解,找到自己的解答」 …
ZnS + O2 = ZnO + SO2 - Chemical Equation Balancer
ZnS + O2 = ZnO + SO2 is a Double Displacement (Metathesis) reaction where two moles of Zinc Sulfide [ZnS] and three moles of Dioxygen [O 2] react to form two moles of Zinc Oxide [ZnO] and two moles of Sulfur Dioxide [SO 2]
ZnS + O2 = ZnO + SO2 - Balanced chemical equation, limiting …
1 ZnS + 1 O 2 = 1 ZnO + 1 SO 2 For each element, we check if the number of atoms is balanced on both sides of the equation. Zn is balanced: 1 atom in reagents and 1 atom in products.
How to Balance ZnS + O2 = ZnO + SO2 (Zinc sulfide - YouTube
2019年3月23日 · To balance ZnS + O2 = ZnO + SO2 you'll need to be sure to count all of atoms on each side of the chemical equation. Once you know how many of each type of atom you can only change the...
ZnS + O2 = ZnO + SO2 - Trình cân bằng phản ứng hoá học
Cân bằng phương trình hay phản ứng hoá học ZnS + O2 = ZnO + SO2 bằng cách sử dụng máy tính này!
硫化锌和氧气反应 - 百度知道
硫化锌和氧气之间的反应可以描述为一种化学反应:2ZnS(s)+3O2(g)→2ZnO(s)+2SO2(g)。 在这个反应中,硫化锌是反应的起始物质,氧气是反应的终止物质,中间物质则是氧化锌与二氧化硫。 反应过程中释放出来的大量热量,使反应物质瞬间升温,经历短暂时间后,反应终止,形成最终产物。 在这个反应中,硫化锌和氧气反应生成氧化锌和二氧化硫。 这是一个氧化还原反应,其中硫化锌被氧化成氧化锌,氧气被还 …
ZnS + O2 = ZnO + SO2 Redox Reaction - ChemicalAid
2ZnS + 3O2 = 2ZnO + 2SO2 is a redox reaction where S is oxidized and O is reduced. ZnS is a reducing agent (i.e. it lost electrons) and O 2 is a oxidizing agent (i.e. it gained electrons).
ZnS + O2 → SO + ZnO - 配平的方程式 | 线上化学方程式!
已求解并配平的化学方程式 ZnS + O2 → SO + ZnO 具有完整的产物. 请求补充完整产物并配平方程. 如果未启用JavaScript,某些功能可能无法正常运行。
[FREE] Balance the following chemical equation: (a) ZnS + O_2 → …
2024年2月20日 · The balanced chemical equation for the reaction of ZnS and O 2 is 2 ZnS + 3 O 2 → 2 ZnO + 2 SO 2 . This was achieved by balancing the atoms of each element on both sides. You ensure that zinc and sulfur are equal, and then adjust the oxygen atoms accordingly.
Balance the following chemical equation.a. ZnS + O 2 ZnO + SO 2
Right, we need 3 O. This is an odd-even condition, ie odd number on one side and even on the other. So we convert both to odd, by putting 2ZnO on right. Now , balance S on right by putting 2 SO2 . Now, only O is unbalanced. Right we have 6 O, left ee to have only 2. So multiply O2 by 3, to get 6 on both sides.