SOLVED: Lead(II) nitrate and ammonium iodide react to form lead(II) iodide and ammonium nitrate according to the reaction Pb(NO3)2(aq) 2NH4I(aq) yields to PbI2(s) 2NH4NO3(aq) What volume of a 0.430 M NH4I solution is required to react with 133 mL of a 0.580 M Pb(NO3)2 solution?How many moles of PbI2 are formed from this reaction?

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Ammonium iodide dissociates reversibly to ammonia and hydrogen iodide if the salt is heated to a sufficiently high temperature. NH4 I(s) ⇄NH3(g) HI(g) Some ammonium iodide is placed in a flask, which is then heated to 400^∘ C. If the total pressure in the flask when equilibrium has been achieved is 705 mm Hg, what is the value of Kp (when partial pressures are in atmospheres)? | Numerade