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The points of intersection of the parabolas y^2 = 5x and x^2 = 5y lie on the line
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SOLVED: Solve the initial value problem 2yy' 5 = y^2 5x with y(0) = 4.a. To solve this, we should use the substitution method. With this substitution:b. After the substitution from the previous part, we obtain the following linear differential equation in y, U, u":The solution to the original initial value problem is described by the following equation in y, x:
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